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@ -2,6 +2,28 @@ |
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#include <stdio.h> |
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void displayArray(int arr[], size_t size); |
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void displayArrayPtr(int *arr, size_t size); |
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void displayArray(int arr[], size_t size) { |
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for (size_t i = 0; i < size; i++) { |
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// both variants are possible |
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printf("%d\n", arr[i]); |
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//printf("%d\n", *(arr + i)); |
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} |
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} |
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void displayArrayPtr(int *arr, size_t size) { |
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for (size_t i = 0; i < size; i++) { |
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// both variants are possible |
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printf("%d\n", *(arr + i)); |
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//printf("%d\n", arr[i]); |
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} |
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} |
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int main(void) { |
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int vector[5] = {1,2,3,4,5}; |
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@ -20,31 +42,48 @@ int main(void) { |
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// pointer notation and arrays |
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int value = 3; |
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for(size_t index = 0; index < sizeof(vector)/sizeof(int); index++) { |
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for (size_t index = 0; index < sizeof(vector)/sizeof(int); index++) { |
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// all following operations are equivalent |
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*pv++ *= value; |
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//pv[index] *= value; |
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//*(pv + index) *= value; |
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//vector[index] *= value; |
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} |
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for(size_t index = 0; index < sizeof(vector)/sizeof(int); index++) { |
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for (size_t index = 0; index < sizeof(vector)/sizeof(int); index++) { |
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printf("vector[%zu]: %d\n", index, vector[index]); |
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} |
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// using malloc to create a one-dimensional array |
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pv = (int*) malloc(5 * sizeof(int)); |
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for (size_t i = 0; i < 5; i++) |
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{ |
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for (size_t i = 0; i < 5; i++) { |
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pv[i] = i + 1; |
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} |
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for (size_t i = 0; i < 5; ++i) |
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{ |
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for (size_t i = 0; i < 5; ++i) { |
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*(pv + i) = i + 1; |
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} |
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for(size_t index = 0; index < 5; index++) { |
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printf("pv[%zu]: %d\n", index, pv[index]); |
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} |
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// passing array to function using array notation |
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displayArray(vector, sizeof(vector)/sizeof(int)); |
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// passing array to function using pointer notation |
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displayArrayPtr(vector, sizeof(vector)/sizeof(int)); |
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// using one-dimensional array of pointers |
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{ |
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int *arr[5]; |
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for (size_t i = 0; i < 5; i++) { |
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// both variants are equivalent |
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arr[i] = (int*) malloc(sizeof(int)); |
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*arr[i] = i; |
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//*(arr + i) = (int*) malloc(sizeof(int)); |
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//**(arr + i) = i; |
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} |
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} |
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return 0; |
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} |